User:IssaRice/Tao's notation for limits: Difference between revisions

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The additional definition is this: if <math>f : X \to \mathbf R</math>, then we define <math>\lim_{x\to x_0} f(x) := \lim_{x\to x_0;\, x \in X} f(x)</math>. In other words, by default we assume that the limit is taken over the entire domain of the function.
The additional definition is this: if <math>f : X \to \mathbf R</math>, then we define <math>\lim_{x\to x_0} f(x) := \lim_{x\to x_0;\, x \in X} f(x)</math>. In other words, by default we assume that the limit is taken over the entire domain of the function.


Now, given <math>f : X \to \mathbf R</math> and some <math>E \subseteq X</math>, we have <math>f|_E : E \to \mathbf R</math>. Thus, <math>\lim_{x\to x_0} f_E(x) = \lim_{x\to x_0;\, x \in E} f|_E(x)</math>.
Now, given <math>f : X \to \mathbf R</math> and some <math>E \subseteq X</math>, we have <math>f|_E : E \to \mathbf R</math>. Thus, <math>\lim_{x\to x_0} f|_E(x) = \lim_{x\to x_0;\, x \in E} f|_E(x)</math>.


By exercise 9.4.6, <math>\lim_{x \to x_0;\, x\in E} f(x) = \lim_{x\to x_0;\, x\in E} f|_E(x)</math>
By exercise 9.4.6, <math>\lim_{x \to x_0;\, x\in E} f(x) = \lim_{x\to x_0;\, x\in E} f|_E(x)</math>


Combining these two equalities, we have <math>\lim_{x \to x_0;\, x\in E} f(x) = \lim_{x\to x_0} f_E(x)</math> as promised.
Combining these two equalities, we have <math>\lim_{x \to x_0;\, x\in E} f(x) = \lim_{x\to x_0} f|_E(x)</math> as promised.

Revision as of 03:00, 1 December 2018

Tao's notation for a limit is limxx0;xEf(x).

Can we write this in a more standard way? basically, if we give one additional definition, we have the very appealing formula limxx0;xEf(x)=limxx0f|E(x).

The additional definition is this: if f:XR, then we define limxx0f(x):=limxx0;xXf(x). In other words, by default we assume that the limit is taken over the entire domain of the function.

Now, given f:XR and some EX, we have f|E:ER. Thus, limxx0f|E(x)=limxx0;xEf|E(x).

By exercise 9.4.6, limxx0;xEf(x)=limxx0;xEf|E(x)

Combining these two equalities, we have limxx0;xEf(x)=limxx0f|E(x) as promised.