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| | || <math>\{\{a_1, \ldots, a_k\} : a_1,\ldots, a_k \in A\}</math> || <math>\sum_{i=1}^k \binom n i</math> | | | || <math>\{\{a_1, \ldots, a_k\} : a_1,\ldots, a_k \in A\}</math> || <math>\sum_{i=1}^k \binom n i</math> |
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| | || <math display="inline">\{ f : A \to \mathbf N \mid \sum_{a \in A} f(a) = k\}</math> | | | || <math display="inline">\{ f : A \to \mathbf N \mid \sum_{a \in A} f(a) = k\}</math> (multisets with cardinality <math>k</math>) || |
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| | || <math>\{\{a_1, \ldots, a_n\} : a_1,\ldots, a_n \in A\}</math> || <math>\sum_{i=1}^n \binom n i = 2^n - 1</math> (a quick way to see this identity is that we want the power set without the empty set) | | | || <math>\{\{a_1, \ldots, a_n\} : a_1,\ldots, a_n \in A\}</math> || <math>\sum_{i=1}^n \binom n i = 2^n - 1</math> (a quick way to see this identity is that we want the power set without the empty set) |
Latest revision as of 02:38, 14 August 2019
Let
be a set with
elements, and let
be a set with
elements.
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Set representing counting problem |
number of ways to count
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Pick things from with replacement |
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(multisets with cardinality ) |
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(a quick way to see this identity is that we want the power set without the empty set)
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