User:IssaRice/Moral public goods example: Difference between revisions

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So to solve for the highest tax that the nobles are willing to pay, we want to find <math>a > 0</math> such that <math display=inline>u(x_n, x_n/\alpha) = u(x_n - a, x_n/\alpha + \frac{N_n}{N_p}a)</math>.
So to solve for the highest tax that the nobles are willing to pay, we want to find <math>a > 0</math> such that <math display=inline>u(x_n, x_n/\alpha) = u(x_n - a, x_n/\alpha + \frac{N_n}{N_p}a)</math>.


This is <math display=inline>\log x_n + \log(x_n/\alpha) = \log(x_n - a) + \log(x_n/\alpha + \frac{N_n}{N_p}a)</math> which reduces to the following quadratic in <math>a</math>: <math display=inline>x_n(x_n/\alpha) = (x_n - a) (x_n/\alpha + \frac{N_n}{N_p}a)</math>.
This is <math display=inline>\log x_n + \log(x_n/\alpha) = \log(x_n - a) + \log(x_n/\alpha + \frac{N_n}{N_p}a)</math> which reduces to <math display=inline>x_n(x_n/\alpha) = (x_n - a) (x_n/\alpha + \frac{N_n}{N_p}a)</math>, which is quadratic in <math>a</math>. Using the quadratic formula and simplifying, the variable <math>x_n</math> actually drops out, and we get <math display=inline>a = 1 - \frac1\alpha\cdot\frac{N_p}{N_n}</math> as the non-zero solution (the other solution is always zero).

Revision as of 19:56, 26 January 2020

working out the general optimal tax for the example given in https://www.greaterwrong.com/posts/pqKwra9rRYYMvySHc/moral-public-goods

each noble has utility function , where is the noble's own wealth and is the average wealth of a peasant (since the donation/tax is distributed equally among peasants, this is the same as saying the wealth of a single peasant).

a tax of amount shifts the current utility amount to , where is the number of nobles and is the number of peasants. This is because each noble loses , so there is to distribute, and this is divided by the number of peasants.

If each noble starts out with times as much wealth as the average peasant, we have .

So to solve for the highest tax that the nobles are willing to pay, we want to find such that .

This is which reduces to , which is quadratic in . Using the quadratic formula and simplifying, the variable actually drops out, and we get as the non-zero solution (the other solution is always zero).