User:IssaRice/Fundamental theorem of calculus: Difference between revisions
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Another way of looking at this that I saw in one of John Stillwell's books is that <math>\int f(x) \, dx</math> is the sum of infinitely many quantities <math>f(x)\, dx</math>. So the incremental thing you add is <math>f(x)\, dx</math>, i.e. <math>d \int f(x) \, dx = f(x)\, dx</math>. Now if you divide by <math>dx</math> you get <math>\frac{d \int f(x) \, dx}{dx} = f(x)</math>, which again is FTC1. | Another way of looking at this that I saw in one of John Stillwell's books is that <math>\int f(x) \, dx</math> is the sum of infinitely many quantities <math>f(x)\, dx</math>. So the incremental thing you add is <math>f(x)\, dx</math>, i.e. <math>d \int f(x) \, dx = f(x)\, dx</math>. Now if you divide by <math>dx</math> you get <math>\frac{d \int f(x) \, dx}{dx} = f(x)</math>, which again is FTC1. | ||
Finally, let's look at <math>A(x) = \int_a^x f(t)\,dt</math>. What is the rate of change of this area function? As x changes, A(x) changes a bit. The rate of change is jut the height of the graph, since the area increases "one vertical line at a time". Or you can think of it as, "the rate at which area, approximated as a rectangle, changes, is the height of that rectangle". | Finally, let's look at <math>A(x) = \int_a^x f(t)\,dt</math>. What is the rate of change of this area function? As x changes, A(x) changes a bit. The rate of change is jut the height of the graph, since the area increases "one vertical line at a time". Or you can think of it as, "the rate at which area, approximated as a rectangle, changes, as the width of the rectangle changes, is the height of that rectangle". | ||
Now, on to FTC2. | Now, on to FTC2. | ||
Revision as of 01:55, 8 September 2021
There's a typical picture of FTC1 that you see in places like Pugh's analysis book or 3Blue1Brown's video on FTC. This explanation makes sense, but I want point out a few different ways of thinking about the picture. One is, like the 3b1b video says, to look at the incremental area. You get . So then you divide by and take the limit as and get .
Another way of looking at this that I saw in one of John Stillwell's books is that is the sum of infinitely many quantities . So the incremental thing you add is , i.e. . Now if you divide by you get , which again is FTC1.
Finally, let's look at . What is the rate of change of this area function? As x changes, A(x) changes a bit. The rate of change is jut the height of the graph, since the area increases "one vertical line at a time". Or you can think of it as, "the rate at which area, approximated as a rectangle, changes, as the width of the rectangle changes, is the height of that rectangle".
Now, on to FTC2.