User:IssaRice/Logical induction notation: Difference between revisions
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Now each coefficient is a real number, so <math>T_5(\overline{\mathbb V})</math> is an <math>\mathbb R</math>-combination. Note that since <math>T_5\colon \mathcal S \cup \{1\} \to \mathcal{E\!F}_5</math> is a function that takes a sentence or the number <math>1</math> and <math>\overline{\mathbb V}</math> is a valuation sequence (''not'' a sentence or number), there appears to be a type error in writing <math>T_5(\overline{\mathbb V})</math>. What is going on is that we aren't evaluating <math>T_5</math> at <math>\overline{\mathbb V}</math>; rather, we are evaluating ''each coefficient'' of <math>T_5</math>, to convert the range of <math>T_5</math> from <math>\mathcal{E\!F}_5</math> to <math>\mathbb R</math>. | Now each coefficient is a real number, so <math>T_5(\overline{\mathbb V})</math> is an <math>\mathbb R</math>-combination. Note that since <math>T_5\colon \mathcal S \cup \{1\} \to \mathcal{E\!F}_5</math> is a function that takes a sentence or the number <math>1</math> and <math>\overline{\mathbb V}</math> is a valuation sequence (''not'' a sentence or number), there appears to be a type error in writing <math>T_5(\overline{\mathbb V})</math>. What is going on is that we aren't evaluating <math>T_5</math> at <math>\overline{\mathbb V}</math>; rather, we are evaluating ''each coefficient'' of <math>T_5</math>, to convert the range of <math>T_5</math> from <math>\mathcal{E\!F}_5</math> to <math>\mathbb R</math>. | ||
To summarize the types: | |||
* <math>T_5 \colon \mathcal S \cup \{1\} \to \mathcal{E\!F}_5</math> | |||
* <math>T_5[\phi] \colon \mathcal{E\!F}_5</math> | |||
* <math>T_5(\overline{\mathbb V}) \colon \mathcal S \cup \{1\} \to \mathbb R</math> | |||
==External links== | ==External links== | ||
Revision as of 04:16, 3 August 2018
This is in user space because it's not really about machine learning.
| Term | Notation | Type | Definition | Notes |
|---|---|---|---|---|
| -combination | Function application of an -combination uses square brackets instead of parentheses. Why? As far as I can tell, this is because each coefficient is in so is itself a function. This means we have two senses of "application": we can pick out the specific coefficient we want (square brackets), or we can apply each coefficient to return something (parentheses). | |||
| Holdings from against (a -combination) | ||||
| Trading strategy |
Example of a 5-strategy given on p. 18 of the paper:
Since the coefficients ( and ) are in , this is an -combination. Let's call this 5-strategy . We can pick out the coefficient for the term like . But since each coefficient is a feature (which is a function), we can also apply each coefficient to some valuation sequence , like this:
Now each coefficient is a real number, so is an -combination. Note that since is a function that takes a sentence or the number and is a valuation sequence (not a sentence or number), there appears to be a type error in writing . What is going on is that we aren't evaluating at ; rather, we are evaluating each coefficient of , to convert the range of from to .
To summarize the types: