User:IssaRice/Little o notation: Difference between revisions

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Definition (little o at infinity). Let <math>f : \mathbf R \to \mathbf R</math> and <math>g : \mathbf R \to \mathbf R</math> be two functions. We say that <math>f</math> is little o of <math>g</math> at infinity iff for every <math>\epsilon > 0</math> there exists <math>M</math> such that for all <math>x</math>, <math>x > M</math> implies <math>|f(x)| < \epsilon|g(x)|</math>.
Definition (little o at infinity). Let <math>f : \mathbf R \to \mathbf R</math> and <math>g : \mathbf R \to \mathbf R</math> be two functions. We say that <math>f</math> is little o of <math>g</math> at infinity iff for every <math>\epsilon > 0</math> there exists <math>M</math> such that for all <math>x</math>, <math>x > M</math> implies <math>|f(x)| < \epsilon|g(x)|</math>.


Can we write just <math>f \in o(g)</math> or <math>f = o(g)</math> or <math>f(x) \in o(g(x))</math> or <math>f(x) = o(g(x))</math>? In general we can't because for this notation to make sense, we also need to know where the argument <math>x</math> is going. In algorithms, we have <math>x \to \infty</math>, but in analysis (e.g. in some definitions of differentiability) we have <math>x \to 0</math>
 
Can we write just <math>f \in o(g)</math> or <math>f = o(g)</math> or <math>f(x) \in o(g(x))</math> or <math>f(x) = o(g(x))</math>?
 
<div class="toccolours mw-collapsible mw-collapsed" style="overflow: auto;"> In general we can't because for this notation to make sense, we also need to know where the argument <math>x</math> is going. In algorithms, we have <math>x \to \infty</math>, but in analysis (e.g. in some definitions of differentiability) we have <math>x \to 0</math>.</div>

Revision as of 02:37, 27 November 2018

Definition

Definition (little o near a point). Let f:RR and g:RR be two functions, and let aR. We say that f is little o of g near a iff for every ϵ>0 there exists δ>0 such that |xa|<δ implies |f(x)|<ϵ|g(x)|.

Definition (little o at infinity). Let f:RR and g:RR be two functions. We say that f is little o of g at infinity iff for every ϵ>0 there exists M such that for all x, x>M implies |f(x)|<ϵ|g(x)|.


Can we write just fo(g) or f=o(g) or f(x)o(g(x)) or f(x)=o(g(x))?

In general we can't because for this notation to make sense, we also need to know where the argument x is going. In algorithms, we have x, but in analysis (e.g. in some definitions of differentiability) we have x0.